How to use Regex to find a string with only spaces delimiting it? -



i'm trying parse string whitespace delimited.

i using /\b[somestring]\b/

but don't want pick words have any punctuation next it.

so if parsed string: 

"trying to,\n test out,\n trying has taken while.\n trying stuff fun,\n stuck"

with /\btrying to\b/

i find three, want 2 because don't want include

"trying to,"

--edit

expected output

trying trying

if understood correctly question, can use regex lookahead this:

trying to(?=\s)

working demo

the idea search string trying to following space character

edit: if want include having \n, can use:

trying to(?=\s|\\n)

btw, if want include literal space , literal \n, don't need use regex lookahead, simple group this:

trying to(?:\s|\\n)

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