python - How to use a special sequence in substitute pattern in re.sub -
this question has answer here:
i have string, in i'd substitute each [
[[]
, ]
[]]
(at same time). thought doing re.sub:
re.sub(r'(\[|\])', '[\1]', 'asdfas[adsfasd]') out: 'asdfas[\x01]adsfasd[\x01]'
but i'm not getting desired result -- how make re.sub
consider \1
in pattern first matched special group?
you should use r
prefix replacing regex well, otherwise \1
interpreted hex literal:
in [125]: re.sub(r'(\[|\])', r'[\1]', 'asdfas[adsfasd]') out[125]: 'asdfas[[]adsfasd[]]'
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