Android Google Maps OnMapReadyCallback() not happening on Device (works on simulator) -


i created android mobile app uses google maps api generate simple map , put marker on it.

everything works great in android simulator, when use android device, mapview.getmapasync not trigger onmapreadycallback().

another thing noted getting these messages, not sure if related problem. tried update in sdk these messages don't go away:

04-07 20:36:30.990 10487-10487/it.bitrack.fabio.bitrack w/googleplayservicesutil: google play services out of date.  requires 10298000 found 9879448 04-07 20:36:30.992 10487-10487/it.bitrack.fabio.bitrack w/googleplayservicesutil: google play services out of date.  requires 10298000 found 9879448 04-07 20:36:30.993 10487-10487/it.bitrack.fabio.bitrack w/googleplayservicesutil: google play services out of date.  requires 10298000 found 9879448 04-07 20:36:30.994 10487-10487/it.bitrack.fabio.bitrack w/googleplayservicesutil: google play services out of date.  requires 10298000 found 9879448

would know why? code below...

code:

mapview.getmapasync(new onmapreadycallback() {     @override     public void onmapready(googlemap googlemap) {         map = googlemap;         map.addmarker(new markeroptions()         .position(new latlng(asset.latitude, asset.longitude))         .title(asset.networkassetcode));         map.setmaptype(googlemap.map_type_hybrid);         map.movecamera(cameraupdatefactory.newlatlngzoom(new latlng(asset.latitude, asset.longitude), 17));          lastseentextview.settext("last seen: " + asset.datetime);          try {              r.getlocationfromcoordinates(asset.latitude, asset.longitude, new callback() {                 @override public void onfailure(call call, ioexception e) {                     e.printstacktrace();                 }                  @override public void onresponse(call call, response response) throws ioexception {                     try (final responsebody responsebody = response.body()) {                         if (!response.issuccessful()) throw new ioexception("unexpected code " + response);                          headers responseheaders = response.headers();                         (int = 0, size = responseheaders.size(); < size; i++) {                             system.out.println(responseheaders.name(i) + ": " + responseheaders.value(i));                         }                          final string result = responsebody.string();                         log.i("bitrack", "google reverse geolocation\n" + result);                          try {                              getactivity().runonuithread(new runnable() {                                 @override                                 public void run() {                                      json j = new json();                                      updatemapview(j.getaddressfromgeolocationcoordinates(result));                                  }                             });                              } catch (exception e) {                              e.printstacktrace();                          }                     }                 }             });              } catch (exception e) {              e.printstacktrace();          }      } });

i fix issue adding piece of code found in question here:

googleplayservicesutil: google play services out of date. requires 5089000 found 5077534

private boolean checkplayservices() {         googleapiavailability googleapi = googleapiavailability.getinstance();         int result = googleapi.isgoogleplayservicesavailable(getcontext());         if(result != connectionresult.success) {             if(googleapi.isuserresolvableerror(result)) {                 googleapi.geterrordialog(getactivity(), result,                         play_services_resolution_request).show();             }              return false;         }          return true;     }

Comments

Post a Comment

Popular posts from this blog

Command prompt result in label. Python 2.7 -

i want put result(output) of shell command label. command works, label shows "0", however, in command prompt, result shown correctly, need showed in label. doing ubuntu. myg1 = button(root, text="rodyti informacija", command=lambda: gauti()) myg1.pack(side=bottom) def gauti(): imti = tekstas.get("1.0", "end-1c") info = subprocess.call("id '{imti}' ".format(imti=imti), shell=true) w = label(root, text= info) w.pack(side = bottom) subprocess.call() returns exit code of process created (in case 0 success). if want text output of process, should instead call subprocess.check_output() .
Read more

javascript - How do I use URL parameters to change link href on page? -

i change href value of link using url parameters. example: default <a id="dlink" href="link-1">link</a> but, when user goes https://url.com/?dlink=link-2 it swaps out link new link <a id="dlink" href="link-2">link</a> first need value url. if you're not using javascript framework can create function using jquery. please check get url parameter jquery or how query string values in js it. after that, element "a" id , set value there. $("#dlink").attr("href", hreffromparam);
Read more

amazon web services - AWS Route53 Trying To Get Site To Resolve To www -

so have domain nameservers pointed aws route 53. site hosted on ec2 instance , reachable resolves site.com, if input www.site.com. i'm curious how site resolve www.site.com. have under route53 domains hosted zone 2 additional record sets outside of ns , soa: a site.com ec2 elastic ip cname www.site.com ec2 public dns i can reach site using both site.com , www.site.com, resolve site.com. there way make if enter either, resolves www.site.com? at first, both should record set. a site.com ec2 elastic ip www.site.com ec2 elastic ip and need redirect setting in web server (nginx, apache, ..) following. (source: how redirect www non-www nginx on centos 7 ) redirect non-www www if want redirect users plain, non-www domain www domain, add server block: server { server_name example.com; return 301 $scheme://www.example.com$request_uri; } save , exit. configures nginx redirect requests "example.com" "www.example.com". not...
Read more