java - Comparing Arrays for common integer -

newbie here , new java itself. working on little project , stumped at. code has 2 arrays, passes these arrays down method. @ point method supposed , compare arrays, find highest common int in case program 10, program take 10 , return main printed out, program assuming possible there no common number in case print out -1. here code far.

public class arraycompare {    public static void main(string [] args)    {       int [] arraya = {2, 4, 6 , 8, 10, 12};       int [] arrayb = {3, 4, 7 , 10, 11,13};        int result = largestincommon(arraya , arrayb);       }     public static int largestincommon( int [] a, int[] b)    {       int counter = 0;        for( int x = 0; x < a.length; x++)       {          if(a[0]==b[x])          {           for(int y = 0; y < b.length; y++)             }         }   } } 

loop on elements of 2 arrays. check if every element equals other , higher last higher element. if is, new higher element

    int[] arraya = { 2, 4, 6, 8, 10, 12 };     int[] arrayb = { 3, 4, 7, 10, 11, 13 };     int higher = -1;      (int = 0; < arraya.length; a++) {         (int b = 0; b < arrayb.length; b++) {             if (arraya[a] == arrayb[b] && arraya[a] > higher) {                  higher = arraya[a];             }         }     }     system.out.println(higher); 

output:

10 

your error compare element before entering second loop. check if first element of arraya[] exists in arrayb[] , never set , return new higher value