oracle - SQL Query to find difference between two times - 


date                  |  id |    param_type 07-08-2012 10:10:53 am| 5613|   input 07-08-2012 10:10:59 am| 5613|   output 07-08-2012 10:16:34 am| 5624|   input 07-08-2012 10:16:42 am| 5624|   output 07-08-2012 08:09:08 am| 5503|   input 07-08-2012 08:09:15 am| 5503|   output

table name : emp_records want display time difference between input , output,as single record.

for example : 

   date               |id   |  param_type 07-08-2012 10:10:53 am| 5613|   input 07-08-2012 10:10:59 am| 5613|   output

as

id  |difference 5613| 6 min

you can use lag analytic function:

select id,        ( output_date - input_date ) * 24 * 60 minutes_difference   (   select id,          "date" output_date,          lag( case param_type when 'input' "date" end )            ignore nulls on ( partition id order "date" ) input_date,          param_type     emp_records )  param_type = 'output';

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