linux - I want to check if some given files contain more then 3 words from an input file in a shell script -

my first parameter file contains given words , rest other directories in i'm searching files, contain @ least 3 of words 1st parameter

i can print out number of matching words, when testing if it's greater 3 gives me error: test: many arguments

here's code:

#!/bin/bash  file=$1 shift 1  in $*     j in `find $i`             if test -f "$j"                     if test grep -o -w "`cat $file`" $j | wc -w -ge 3                             echo $j             fi         fi     done   done 

you first need execute grep | wc, , compare output 3. need change if statement that. since using backquotes, cannot nest them, can use other syntax $(command), equivalent `command`:

if [ $(grep -o -w "`cat $file`" $j | wc -w) -ge 3 ]     echo $j fi