excel - Find first vowel in a column and display it in the next column -
what trying basic. want loop through full column "i" , display vowel in column "m". want loop through 1000+ rows in column. here got far, error referencing object-based.
private sub form_load() dim mystring string, long, asciinum string, f long f = 1 rows.count rows(f, "i") = mystring = 1 len(mystring) asciinum = lcase(mid(mystring, i, 1)) if asciinum = "a" or asciinum = "e" or asciinum = "i" or asciinum = "o" or asciinum = "u" rows(f, "m") = "first vowel " + asciinum exit end if next exit next end sub probably error array , for...loop?
you have value assignment backwards , need use cells instead of rows.
option explicit private sub form_load() dim mystring string, long, asciinum string, f long f = 1 rows.count mystring = cells(f, "i").value2 = 1 len(mystring) asciinum = lcase(mid(mystring, i, 1)) if asciinum = "a" or asciinum = "e" or asciinum = "i" or asciinum = "o" or asciinum = "u" cells(f, "m") = "first vowel " + asciinum exit end if next exit next end sub this should work on activesheet should start getting practice of used defined parent worksheet , use cells values in them instead of looping way down bottom of worksheet.
option explicit private sub form_load() dim mystring string, long, asciinum string, f long worksheets("sheet1") f = 1 .cells(.rows.count, "i").end(xlup).row mystring = .cells(f, "i").value2 = 1 len(mystring) asciinum = lcase(mid(mystring, i, 1)) if asciinum = "a" or asciinum = "e" or asciinum = "i" or asciinum = "o" or asciinum = "u" .cells(f, "m") = "first vowel " + asciinum exit end if next next f end end sub i've removed second exit for continues outer loop.
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