php - How to return multiple views in one function in laravel for same route -

it quite difficult explain question. hope able understand it.

for project have master layout contains header , yield of content.

master.blade.php

 @include('partials.header')     <div class="container-fluid main-con">         @yield('content')         @include('partials.footer')     </div>   

now on main public route raturning method.

web.php

route::get('/', [     'uses' => 'productcontoller@getindex',     'as' => 'product.maincats' ]); 

productcontoller.php

class productcontoller extends controller {      public function getindex(){         $ad_cats = mainaddtype::orderby('title')->get();         return view( 'shop.main-categories-page', ['mediacats' => $ad_cats]);     } } 

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now query is, 'main-categories-page' yielding in content section of master. want same data of mainadtype in header also. want return view of header on same function. please if u understand it.

what trying is,

 public function getindex(){         $ad_cats = mainaddtype::orderby('title')->get();         return view( 'shop.main-categories-page', ['mediacats' => $ad_cats]);         return view( 'partials.header', ['mediacats' => $ad_cats]);     } 

but know cant return in way. in advance.

you can access variable in header well. have check see if variable exists don't errors when load other views.

@if(!empty($mediacats))    // awesome stuffs $mediacats @endif 

this way data available when on index page.

if want data available in views, can use laravel view composer. official docs:

view composers callbacks or class methods called when view rendered. if have data want bound view each time view rendered, view composer can organize logic single location

hope helps.