How to convert string to integer in a shell script? -

i have file of 4gb in /var/tmp/test/dsk/file.1 in path. can see through solaris linux command follows:

-bash-4.4# du -h /var/tmp/test/dsk/file.1 4.0g /var/tmp/test/dsk/file.1 

i want disk size did following.

 disk=`du -h /var/tmp/test/dsk/file.1| awk '{print $1}'|tr -d '.g'` 

which gives me output follows:

-bash-4.4# echo $disk 4.0 

but want compare disk size value 50 , first need convert above output integer, i'm failing that, can in this, have searched not getting exact solution.

sorry don't see probem here :) tool bc accepts whatever format may give:

[ $(bc <<< "$disk>=50") -eq 1 ] 

btw, might want convert human readable size output simple numeric byte size function like:

# converts human readable sizes integer kilobyte sizes # usage numericsize="$(humantonumeric $humansize)" function humantonumeric {     local value="${1}"      local notation     local suffix     local suffixpresent     local multiplier      notation=(k m g t p e)     suffix in "${notation[@]}";         multiplier=$((multiplier+1))         if [[ "$value" == *"$suffix"* ]];             suffixpresent=$suffix             break;         fi     done      if [ "$suffixpresent" != "" ];         value=${value%$suffix*}         value=${value%.*}         # /1024 since convert kilobytes instead of bytes         value=$((value*(1024**multiplier/1024)))     else         value=${value%.*}     fi      echo $value }