python - For Loop and Accumulator Pattern -


an old legend has wise man, when offered reward desired, requested first grandchild receive 1 coin, second grandchild receive twice many first, third receive twice many second, , on. how many coins last grandchild receive? how many coins grandchildren receive in all? function should accept number of grandchildren , return statement addressing both questions. ihave far

def grandchild_coins(number_of_grand_children):# not finished     coins=1     grand_child in range(number_of_grand_children):         coins=coins*2     return ' grand child' + str(grand_child) + ' ' + str(coins) + ' coins'    grandchild_coins(10)    out[33]: ' grand child9 1024 coins'

how list how coins each grand child has ?

thanks guys

def grandchild_coins(number_of_grand_children):               # initalizes coins 1     coins=1     total_coins=[]  # grand_child in range entered code ran grand_child in range(number_of_grand_children):      # if grand_child number not 0 coins = coins*2     if grand_child !=0:         coins=coins*2         # prints coins each grand_child     print ' grand_child' + str(grand_child)  + str( coins)     total_coins.append(coins)          # returns total amount of coins    return sum(total_coins) + ' coins in total'

it because return last element in range (grand_child equal 9 - range (10) means iteration 0 9) so, advice (keeping close code):

def grandchild_coins(number_of_grand_children):     coins=1     grand_child in range(number_of_grand_children):         if grand_child != 0: #where need keep 1 coinn first son             coins=coins*2         print(' grand child' + str(grand_child + 1) + ' ' + str(coins) + 'coins')       return true  grandchild_coins(10)

and output:

 grand child1 1coins  grand child2 2coins  grand child3 4coins  grand child4 8coins  grand child5 16coins  grand child6 32coins  grand child7 64coins  grand child8 128coins  grand child9 256coins  grand child10 512coins

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