xslt 2.0 - Separating data into groups -


i think i'm missing simple here. have source xml file

<inventory division="b"  xmlns:xsl="http://www.w3.org/1999/xsl/transform">     <stackgroup name="warehouse">         <stack>              <mainstack name="primary">                 <mainstackgroup name="group_primary">                     <mainstacklayer sequence="1">                         <stacklayerref id="layer_1"/>                     </mainstacklayer>                 </mainstackgroup>             </mainstack>              <mainstack name="secondary">                 <mainstackgroup name="group_secondary">                     <mainstacklayer sequence="2">                         <stacklayerref id="layer_2"/>                     </mainstacklayer>                 </mainstackgroup>             </mainstack>          </stack>     </stackgroup> </inventory>

i'm applying stylesheet:

<?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/xsl/transform" version="2.0">     <xsl:output method="xml" indent="yes"/>      <xsl:template match="/">         <mainstack>              <numberofstacks>                 <xsl:value-of select="count(/inventory/stackgroup/stack/mainstack)"/>             </numberofstacks>              <stackdisplayorder>                 <xsl:apply-templates select="/inventory/stackgroup/stack/mainstack" mode="order"/>             </stackdisplayorder>              <xsl:apply-templates select="/inventory/stackgroup/stack/mainstack" mode="stacklist"/>          </mainstack>     </xsl:template>      <xsl:template match="/inventory/stackgroup/stack/mainstack" mode="order">         <index><xsl:value-of select="position() - 1" /></index>     </xsl:template>      <xsl:template match="/inventory/stackgroup/stack/mainstack" mode="stacklist">         <stack>             <index><xsl:value-of select="position() - 1" /></index>             <name>                 <xsl:value-of select="/inventory/stackgroup/stack/mainstack/@name"/>             </name>             <groupname>                 <xsl:value-of select="/inventory/stackgroup/stack/mainstack/mainstackgroup/@name"/>             </groupname>             <sequenceno>                 <xsl:value-of select="/inventory/stackgroup/stack/mainstack/mainstackgroup/mainstacklayer/@sequence"/>             </sequenceno>             <layerno>                 <xsl:value-of select="/inventory/stackgroup/stack/mainstack/mainstackgroup/mainstacklayer/stacklayerref/@id"/>             </layerno>         </stack>     </xsl:template>  </xsl:stylesheet>

i following output:

<?xml version="1.0" encoding="utf-8"?> <mainstack>    <numberofstacks>2</numberofstacks>    <stackdisplayorder>       <index>0</i`enter code here`ndex>       <index>1</index>    </stackdisplayorder>    <stack>       <index>0</index>       <name>primary secondary</name>       <groupname>group_primary group_secondary</groupname>       <sequenceno>1 2</sequenceno>       <layerno>layer_1 layer_2</layerno>    </stack>    <stack>       <index>1</index>       <name>primary secondary</name>       <groupname>group_primary group_secondary</groupname>       <sequenceno>1 2</sequenceno>       <layerno>layer_1 layer_2</layerno>    </stack> </mainstack>

the template finds 2 matches , concatenates data both. how can separate them?

thanks in advance!

use relative paths change e.g.

        <name>             <xsl:value-of select="/inventory/stackgroup/stack/mainstack/@name"/>         </name>

to

        <name>             <xsl:value-of select="@name"/>         </name>

and on paths in template.


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