MATLAB swapping rows with zero in its pivot position, partial pivoting? -
i want matrix turn into a = 1 2 -1 4 5 1 -6 7 5 6 0 0 4 7 5 0 -3 4 7 7 1 5 1 5 6 this kind of matrix. a = 1 2 -1 4 5 1 -6 7 5 6 1 5 1 5 6 0 -3 4 7 7 0 0 4 7 5 so, row 0 in pivot position should go down. i able find rows 0 in pivots using following code: count=0; i=1:n j=1:n if a(i,j)~=0 break else count=count+1; row(count)=i; break end end end row >> row = 3 4 but don't know how can proceed after point. want make code applies kind of matrix. plz help. i think need: a =[1 2 -1 4 5; 1 -6 7 5 6; 0 0 4 7 5; 0 -3 4 7 7; 1 5 1 5 6]; % find last 0 in each row [val,lastzero...