python - Read multiple CSV Files, cut at empty row, sorted array of column -

i read multiple csv files python 3.6, skip header , stop @ first empty row. extract fourth column of each csv file fill array sorted shown @ end.

my files: csv files

thats code far i'm not happy output order , maybe there more elegant way?

csvdata_d=[]  in range(timestep):   # timestep = number of files     open(csvname[i]) f:         reader = csv.reader(f)         readerlist=list(reader)         row in readerlist[2:]: # skip 2 header lines              if len(row) == 0:      # empty line definition                 break                         else:                 row=list(row)                 csvdata_d.append(row[3]) # fourth column  print(csvdata_d) 

my output is: csvdata_d=['1.1', '1.2', '1.3', '2.1', '2.2', '2.3', '3.1', '3.2', '3.3']

but want [['1.1','2.1','3.1'],['1.2','2.2','3.2'],['1.3','2.3','3.3']]

thanks help.

i solved numpys genfromtxt module , loop find empty row

headsize=2 #lines toskip @ beginning csvdata=[] measuredata=[]  open (csvname[0])as f: #measurement of file first empty row     reader = csv.reader(f)     readerlist=list(reader)     lengthfile=(len(readerlist))     row in readerlist[headsize:]:         if len(row)== 0:             break         else:           measuredata.append(list(row[3]))    skfooter=int(lengthfile-(len(measuredata)+(headsize+1))) #calc number of rows below empty line  in range(timestep):     data=np.genfromtxt((csvname[i]), delimiter=',', skip_header=headsize,   usecols=3, skip_footer=skfooter)     csvdata.append(data)   s=[] in range (len(csvdata[0])):     s.append([item[i] item in csvdata])     print(s)